Basics of Mathematics

The answer to Question 4 seems to be 13, because

8, -7, 6, -5, 4, -3, 2, -1, 0, -1, 2, -3, 4, -5, 6, -7, 8, -9, 10, -11, 12, -13, 14, -15, 16, -17, 18 are the first 27 numbers. The sum of them is 13. It seems that you have not counted the 27th number 18, hence, the mistake. :)
 
Suren - I think it means which of these numbers can also be a divisor.

What is a divisor of a number that, when devided by 24, gives a remained of 21.

So find out which number divided by 24 gives 21 as a remainder, and see by which number of the options it can be divided by. Atleast thats what I would have done.

I'll continue my attempt at question 1 later, I'm curious now.
 
The answer to Question 4 seems to be 13, because

8, -7, 6, -5, 4, -3, 2, -1, 0, -1, 2, -3, 4, -5, 6, -7, 8, -9, 10, -11, 12, -13, 14, -15, 16, -17, 18 are the first 27 numbers. The sum of them is 13. It seems that you have not counted the 27th number 18, hence, the mistake. :)

Oh thank you... Really, a bad silly mistake :mad

That's because you're in year 7 nerd.

Since he is in just year 7, all these would definitely look like greek and latin.. And perhaps, he would also be learning all these as he climbs up his life ladder. :)

Suren - I think it means which of these numbers can also be a divisor.

What is a divisor of a number that, when devided by 24, gives a remained of 21.

So find out which number divided by 24 gives 21 as a remainder, and see by which number of the options it can be divided by. Atleast thats what I would have done.

So, which means, x = 24k + 21. where x is the number. K can be anything. Say k =1 we get, 45 as the number. Which has divisors like 1,3,5,9.... Since K can be anything, it's not possible to find exact solutions i guess.

Or question is missing something very crucial.


I'll continue my attempt at question 1 later, I'm curious now.

Hey, I found the solution of the first problem yesterday which i mentioned here,

http://www.planetcricket.org/forums/showpost.php?p=1192333&postcount=11
 
Yea, but I want to find it out myself! :p

And yup, n = 24K + 21. K can be anything. Are you doing an examination for a management course by any chance?
 
Question 2.

I haven't tested this out, but my guess is that it would be (6*2) + (7*8)

The method I used is:

One way would be to ensure that one bag has a carrot at all times.
So 10 carrots, 5 radishes in one and 1 radish in an other.
10 carrots, 4 radishes in one and 2 in another.
So on, that can done 6 times till 10 carrots, 0 radishes in one and 6 radishes in another.

This can also be done with:
9 carrots 6 radishes in one, 1 carrot in another
9 carrots, 5 radishes in one, 1 radish 1 carrot in another
(Note that here it can be done 7 times and not 6)

And so on with decreasing numbers of carrots till it is
1 carrot, 6 radishes in one, 9 carrots in another
1 carrot, 5 radishes in one, 9 carrots, 1 radish in another.
(Here it is 6 times again)

So that is 10 ways it can be done, if we try to keep one carrot in the bag at all times (1 carrot in one bag, 2 in one bag, 3 in one bag...9 in one bag, 10 in one bag.)

So it is (6*2) + (7*8)

I believe this is the solution. Because if we do it with keeping the radishes side consistent, it would be just the same as what we get here, right?

So the answer for me would be 12 + 56 = 78.

Is that right?
 
I was doing it more like probability. I figured out all the possible combinations, like we do in probability, and then when asked what are the odds of us gettin 3 carrots, 3 radishes in one bag, and 7 carrots, 3 radishes in another, I could give it.
 
If n is divided by 24, the remainder is 21. Which of the following is the divisor of n?
I'm guessing its a multiple choice exam, so I suspect only one "of the following" will be correct. :)
 
Are you doing an examination for a management course by any chance?

Well, it's not the exam for Management.. but it's an entry level exam for the Masters degree. I am trying for MS in ComputerScience since I want to take my life path in techy side. :)

And Also I gave a go at it last week and I ended up in getting 1100/1600. 720/800 in Quants(Maths) and 380/800 in Verbal.

I hope I get into some good univs with this score since my academics score seems to be better with 86% and university rank(20th rank among 7000 students) in college level. Lets see:upray
 

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