A plane mirror is made of glass slab ( R.I.=1.5) 2.5 cm thick and silvered on back. A point object is placed 5 cm in front of the unsilvered face of the mirror. What will be the position of final image from the unsilvered face ?
Thats easy,
Assuming normal incidence, n: refractive index, t: thickness of glass, d: distance of object.
Apparent image after refraction wrt unsilvered glass,
= nd, wrt mirror = nd + t,
Image off mirror wrt itself,
= nd + t, wrt unsilvered glass = nd + 2t,
Image after refraction,
= (nd + 2t)/n.
Here wrt means with respect to.